Fizz Buzz¶
Time: O(N); Space: O(1); easy
Write a program that outputs the string representation of numbers from 1 to N. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
Example 1:
Input: n = 15
Output:
[
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
[1]:
class Solution1(object):
def fizzBuzz1(self, n):
"""
:type n: int
:rtype: List[str]
"""
result = []
for i in range(1, n+1):
if i % 15 == 0:
result.append("FizzBuzz")
elif i % 5 == 0:
result.append("Buzz")
elif i % 3 == 0:
result.append("Fizz")
else:
result.append(str(i))
return result
[2]:
s = Solution1()
N = 15
assert s.fizzBuzz1(N) == [
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
[3]:
class Solution2(object):
def fizzBuzz(self, n):
"""
:type n: int
:rtype: List[str]
"""
L = [str(x) for x in range(n + 1)]
L3 = range(0, n + 1, 3)
L5 = range(0, n + 1, 5)
for i in L3:
L[i] = 'Fizz'
for i in L5:
if L[i] == 'Fizz':
L[i] += 'Buzz'
else:
L[i] = 'Buzz'
return L[1:]
[5]:
s = Solution2()
N = 15
assert s.fizzBuzz(N) == [
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
[6]:
class Solution3(object):
def fizzBuzz(self, n):
return ['Fizz' * (not i % 3) + 'Buzz' * (not i % 5) or str(i) for i in range(1, n + 1)]
[7]:
s = Solution3()
N = 15
assert s.fizzBuzz(N) == [
"1",
"2",
"Fizz",
"4",
"Buzz",
"Fizz",
"7",
"8",
"Fizz",
"Buzz",
"11",
"Fizz",
"13",
"14",
"FizzBuzz"
]
[18]:
class Solution4(object):
def fizzBuzz(self, n):
return ['FizzBuzz'[i % -3 & -4:i % -5 & 8 ^ 12] or i for i in range(1, n + 1)]
[19]:
s = Solution4()
N = 15
assert s.fizzBuzz(N) == [
1,
2,
"Fizz",
4,
"Buzz",
"Fizz",
7,
8,
"Fizz",
"Buzz",
11,
"Fizz",
13,
14,
"FizzBuzz"
]